BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    The phase difference between two points separated by 6 m in a wave of frequency 100 Hz is 540° . The wave velocity is:

    A)  400 m/s                              

    B)  200 m/s

    C)  100 m/s                              

    D)  50 m/s

    Correct Answer: A

    Solution :

                                                As wavelength \[\lambda \] corresponds to \[{{360}^{o}}\], So,   \[\frac{\lambda }{360}=\frac{6}{{{540}^{o}}}\] or  \[\lambda =\frac{6\times 360}{540}=4m\] Velocity \[\upsilon =n\lambda =100\times 4=400m/s\]


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