A) 0.1 mA
B) 1 mA
C) 9 mA
D) near by 11 mA
Correct Answer: D
Solution :
Given, \[{{i}_{c}}=10mA,{{i}_{c}}=\frac{9}{10}\times {{i}_{e}}\] So, \[10=\frac{9}{10}\times {{i}_{e}}\] or \[{{i}_{e}}=\frac{100}{9}\approx 11mA\]You need to login to perform this action.
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