A) lone pair-lone pair repulsion
B) lone pair-bond pair repulsion
C) bond pair-bond pair repulsion
D) high electronegativity of oxygen
Correct Answer: A
Solution :
The hybridisation of oxygen in water molecule is \[s{{p}^{3}}\] so water must be tetrahedral and have bond angle 109°28. But due to the presence of two lone pair of electrons on oxygen atom (repulsion between lone pair-lone pair) the bond angle decreases about 104.5° and the geometry becomes distorted tetrahedral or V-shape.You need to login to perform this action.
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