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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    A vehicle of mass 100 kg is moving with a velocity of 5 m/s. To stop it in \[\frac{1}{10}\] sec, the required force in opposite direction is :

    A)  5000 N                

    B)  2500 N

    C)  500 N                                   

    D)  100 N

    Correct Answer: A

    Solution :

                                                                                         Using the relation, \[F\Delta t=\Delta p\] Given, \[m=10kg,\upsilon =5m/s,\,t=\frac{1}{10}\sec \] So, \[F=\frac{m\upsilon }{\Delta t}=\frac{100\times 5}{1/10}\] \[=5000N\]


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