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BVP Medical BVP Medical Solved Paper-2001

  • question_answer
    If the concentration of \[M{{g}^{2+}}\] is 0.01 M, the electrode potential of \[M{{g}^{2+}}/Mg\] electrode will be (Given that \[{{E}^{o}}\,M{{g}^{2+}}\]\[Mg=-2.36V\]):

    A)  \[+2.80\]           

    B)  \[-2.80\]

    C)  \[+2.41\]           

    D)  \[-2.41\]

    Correct Answer: D

    Solution :

                    \[{{E}^{o}}_{M{{g}^{2+}}}{{,}_{Mg}}={{E}^{o}}_{M{{g}^{2+}},Mg}\] \[=\frac{0.0591}{2}\log \frac{[M{{g}^{+2}}]}{[Mg]}\] \[=-2.36+\frac{0.0591}{2}\log \frac{0.01}{1}\] \[=-2.36+\frac{0.0591}{2}\log 0.01\] \[=-2.36-0.0591\] \[=-2.4191\]


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