A) \[9\times {{10}^{-6}}J\]
B) \[4.5\times {{10}^{-4}}J\]
C) \[9\times {{10}^{-4}}J\]
D) \[19\times {{10}^{-4}}J\]
Correct Answer: C
Solution :
Increase in energy \[=\frac{1}{2}C(V_{2}^{2}-V_{1}^{2})\] \[=\frac{1}{2}\times 6\times {{10}^{-6}}\left\{ {{20}^{2}}-{{10}^{2}} \right\}\] \[=\frac{1}{2}\times 6\times {{10}^{-6}}\left\{ 400-100 \right\}\] \[=\frac{1}{2}\times 6\times {{10}^{-6}}\times 300\] \[=9\times {{10}^{-4}}J\]
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