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BVP Medical BVP Medical Solved Paper-2002

  • question_answer
    A meter of resistance 5 ohm fitted with a shunt resistance of 1 ohm, is in a circuit in which the current is 0.09 A. The combined resistance of the meter and the shunt is :

    A) \[\frac{5}{6}\Omega \]                                 

    B) \[\frac{5}{6}\Omega \]

    C) \[2\Omega \]                                    

    D) \[6\Omega \]

    Correct Answer: B

    Solution :

                    The shunt wire is connected in parallel with the a meter. so, equivalent resistance \[=\frac{5\times 1}{5+1}=\frac{5}{6}\Omega \]


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