A) \[1\alpha ,1\beta \]
B) \[2\beta {{,}_{1}}{{H}^{1}}\]
C) \[_{1}{{H}^{1}}\]
D) \[_{1}{{H}^{1}},2\alpha \]
Correct Answer: A
Solution :
\[_{92}{{U}^{238}}{{\xrightarrow{{}}}_{91}}P{{a}^{234}}\] Decrease in mass number \[=238-234=4\] \[\therefore \]Number of a-particle \[=\frac{4}{4}=1\] \[\therefore \] \[_{92}{{U}^{238}}{{\xrightarrow{-\alpha }}_{90}}{{X}^{234}}{{\xrightarrow{{}}}_{91}}P{{a}^{234}}\] Now, increase in atomic number \[=91-90=1\] \[\therefore \] Number of \[\beta \] particles = 1
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