BVP Medical BVP Medical Solved Paper-2002

  • question_answer
    In a nuclear reactor 0.01 mg of a nuclear material is totally converted into energy in one sec. Then the power of reactor will be :

    A) 900 MW                              

    B) 450 W

    C) 200 MW                              

    D) 500 W

    Correct Answer: A

    Solution :

                    Power of reactor \[=\frac{E}{t}\] \[=\frac{m{{c}^{2}}}{t}\]                                 \[=\frac{0.01\times {{10}^{-6}}\times {{(3\times {{10}^{8}})}^{2}}}{1}\]                                 \[=1\times {{10}^{-8}}\times 9\times {{10}^{16}}\]                                 \[=9\times {{10}^{8}}\]                                 \[=900\times {{10}^{6}}W\]                                 \[=900MW\]


You need to login to perform this action.
You will be redirected in 3 sec spinner