BVP Medical BVP Medical Solved Paper-2002

  • question_answer Two metal pieces having a potential difference of 800V are 0.02 m apart horizontally. A particle of mass\[1.96\times {{10}^{-15}}\,kg\]is suspended equilibrium between the plates. If e is the elementary charge, then charge on the particle is :

    A)  8e                                         

    B)  6e

    C)  3e                                         

    D)  e

    Correct Answer: C

    Solution :

                    For equilibrium  weight of particle = electrostatic force \[mg=qE\] \[mg=q\left( \frac{V}{d} \right)\] Putting the given values we get \[1.96\times {{10}^{-15}}\times 9.8=q\left( \frac{800}{0.02} \right)\] \[q=\frac{1.96\times {{10}^{-15}}\times 9.8\times 0.02}{800\times 1.6\times {{10}^{-19}}}e\]\[=3e\]


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