A) \[{{S}^{-2}}\]
B) \[O_{2}^{-}\]
C) \[N_{2}^{-}\]
D) \[NO\]
Correct Answer: A
Solution :
Electronic configuration of \[{{S}^{-2}}\] is \[1{{s}^{2}},2{{s}^{2}}2{{p}^{6}},3{{s}^{2}}3{{p}^{6}}\] Since, it has no unpaired electrons, thus it is diamagnetic.
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