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BVP Medical BVP Medical Solved Paper-2002

  • question_answer
    \[\frac{1}{2}\]mole of He is contained in a container  at S.T.P. The heat energy needed to double the pressure of the gas, keeping the volume constant, (heat capacity of the gas is 3J/gmK) is :

    A)  409.5 J                 

    B)  819 J

    C)  1638 J                                  

    D)  3276 J

    Correct Answer: C

    Solution :

                    At constant volume Pressure \[P\propto T\] to double the pressure, temperature should be doubled. Initial temperature = 273K (at S.T.P.) Final temperature \[=2\times 273=546\text{ }K\] Rise in temperature \[\Delta t=546-273=273K\] Mass of \[\frac{1}{2}\] mole \[=\frac{1}{2}\times 4=2g\] Heat \[Q=ms\Delta t\] \[=2\times 3\times 273=1638J\]


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