A) 816
B) 916
C) 1616
D) 2615
Correct Answer: D
Solution :
Energy absorbed by the black body \[E=\sigma A{{T}^{4}}\] \[30kW=5.672\times {{10}^{-8}}\times 4\pi {{(3\times {{10}^{-2}})}^{2}}{{T}^{4}}\] \[30\times {{10}^{3}}=5.672\times {{10}^{-8}}\times 4\pi \times 9\times {{10}^{-4}}\times {{T}^{4}}\] \[{{T}^{4}}=\frac{30\times {{10}^{3}}}{5.672\times {{10}^{-8}}\times 4\pi \times 9\times {{10}^{-4}}}\] \[=46.875\times {{10}^{12}}\] \[T=2.615\times {{10}^{3}}=2615K\]You need to login to perform this action.
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