A) \[C{{l}_{3}}C-COOH\]
B) \[{{F}_{3}}C-COOH\]
C) \[B{{r}_{3}}C-COOH\]
D) \[C{{H}_{3}}COOH\]
Correct Answer: B
Solution :
Due to the greatest -1 effect of fluorine atom \[C{{F}_{3}}-COOH\] is the strongest acid than other acids order of acidic strength is: \[C{{F}_{3}}-COOH>CC{{l}_{3}}-COOH\]\[>CB{{r}_{3}}-COOH>C{{H}_{3}}COOH\]
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