A) \[1.25\times {{10}^{-4}}m/L\]
B) \[12.5\times {{10}^{-2}}m/L\]
C) \[2.50\times {{10}^{-3}}m/L\]
D) \[2.50\times {{10}^{-4}}m/L\]
Correct Answer: B
Solution :
\[Fe{{O}_{(s)}}+C{{O}_{(g)}}\xrightarrow{{}}F{{e}_{(s)}}+C{{O}_{2(g)}}\] At equilibrium \[{{K}_{C}}=\frac{[C{{O}_{2}}]}{[CO]}\] given \[[CO]=2.5\times {{10}^{-2}}mol/litre,\,\,{{K}_{C}}=5.0\] \[5=\frac{[C{{O}_{2}}]}{2.5\times {{10}^{-2}}}\] \[[C{{O}_{2}}]=12.5\times {{10}^{-2}}mol/litre\]You need to login to perform this action.
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