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BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    A beam of ions enters normallyintoauniform magnetic field of\[4\times {{10}^{2}}\]tesla with velocity of \[2\times {{10}^{5}}\] m/s. If the specific charge of the ion is \[5\times {{10}^{7}}\] C/kg, then the radius of the circular path described will be :

    A)  0.10m                  

    B)  0.06 m

    C)  0.20 m                                 

    D)  0.25 m

    Correct Answer: A

    Solution :

                    From the relation \[\frac{m{{\upsilon }^{2}}}{r}=Be\upsilon \] Here:     \[\frac{e}{m}=5\times {{10}^{7}}C/kg\] \[\upsilon =2\times {{10}^{5}}m/s\] \[B=4\times {{10}^{-2}}tesla\] \[r=\frac{m\upsilon }{Be}\]         ??(i) Now in equation (i), we put the given values,                 \[r=\frac{\upsilon }{\frac{e}{m}B}=\frac{2\times {{10}^{5}}}{5\times {{10}^{7}}\times 4\times {{10}^{-2}}}=0.1m\]


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