A) 100 cc
B) 400 cc
C) 104 cc
D) 2.5 cc
Correct Answer: D
Solution :
Applying the ideal gas law \[\frac{{{P}_{1}}{{V}_{1}}}{{{T}_{1}}}=\frac{{{P}_{2}}{{V}_{2}}}{{{T}_{2}}}\] ???(i) Here: \[{{T}_{1}}={{T}_{2}}\] (given) and \[{{P}_{1}}=1\] atm, \[{{V}_{1}}=10cc,\]\[{{P}_{2}}=4atm\] Now from equation (i), \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[10\times 1=4\times {{V}_{2}}\] \[{{V}_{2}}=2.5cc\]
You need to login to perform this action.
You will be redirected in
3 sec
