A) \[4\times {{10}^{-5}}wb/{{m}^{2}}\]
B) \[2\times {{10}^{-5}}wb/{{m}^{2}}\]
C) \[3\times {{10}^{-5}}wb/{{m}^{2}}\]
D) \[8\times {{10}^{-5}}wb/{{m}^{2}}\]
Correct Answer: A
Solution :
Here: i = 20 amp, r = 10 cm \[=10\times {{10}^{-2}}m\] Intensity of magnetic field produced due to straight current carrying wire will be \[B=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2i}{r}\] \[=\frac{{{10}^{-7}}\times 2\times 20}{0.1}=4\times {{10}^{-5}}wb/{{m}^{2}}\]
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