A) \[\frac{3}{4}\] m/s
B) \[\frac{1}{3}\] m/s
C) \[\frac{3}{2}\] m/s
D) \[\frac{2}{3}\] m/s
Correct Answer: D
Solution :
Using law of conservation of momentum \[{{m}_{1}}{{u}_{1}}+{{m}_{2}}{{u}_{2}}=({{m}_{1}}+{{m}_{2}})\upsilon \] Here \[{{m}_{1}}=10kg,{{m}_{2}}=20kg,\,\,\,{{u}_{1}}=2m/s,u=0\] So, \[10\times 2+0=(10+20)\upsilon \] \[\upsilon =\frac{20}{30}=\frac{2}{3}m/s\]
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