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BVP Medical BVP Medical Solved Paper-2003

  • question_answer
    A biconvex lens is made of material of refractive index 1.5 each of radius of curvature of lens surface is 20 cm. The focal length 10 cm to obtain a real image double the size of object will be:

    A)  30 cm                                  

    B)  10 cm

    C)  25 cm                                  

    D)  30 cm

    Correct Answer: A

    Solution :

                    Here: \[\mu =1.5,{{R}_{1}}=20cm,\,\,{{R}_{2}}=-20cm\] From lens makers formula                 \[\frac{1}{f}=(\mu -1)\left( \frac{1}{{{R}_{1}}}-\frac{1}{{{R}_{2}}} \right)\] or            \[\frac{1}{f}=(1.5-1)\left( \frac{1}{20}-\frac{1}{-20} \right)\] or            \[\frac{1}{f}=0.5\times \frac{2}{20}\]  or  \[f=20cm\]


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