A) \[1\times {{10}^{-8}}\]
B) \[1\times {{10}^{-4}}\]
C) \[1\times {{10}^{-6}}\]
D) \[{{10}^{-5}}\]
Correct Answer: A
Solution :
For weak electrolytes, according to Ostwalds dilution law \[\alpha =\sqrt{K.V}\] here, \[\alpha =0.01%=0.0001=1\times {{10}^{-4}}\] \[V=\frac{1}{C}=\frac{1}{1.0}=1litre\] \[\therefore \] \[{{K}_{a}}=\frac{{{\alpha }^{2}}}{V}=\frac{{{(1\times {{10}^{-4}})}^{2}}}{1}\] \[=1\times {{10}^{-8}}\]
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