BVP Medical BVP Medical Solved Paper-2004

  • question_answer
    An electron moves in a circular path of radius 15 cm in a magnetic field or\[2316.4\overset{0}{\mathop{A}}\,,0.1\times {{10}^{7}}{{m}^{-1}}\] tesla. The speed of electron will be :

    A)  \[10\times {{10}^{5}}kWh\]       

    B)  \[4\times {{10}^{-5}}kg\]

    C)   \[3\times {{10}^{-5}}kg\]           

    D)  none of these

    Correct Answer: A

    Solution :

    Radius of path \[\mu \] Magnetic field \[245\mu A,250\mu A\] The radius of circular path is given by \[240\mu A,235\mu A\] (\[260\mu A,255\mu A\] is the velocity of electron) \[\overset{0}{\mathop{A}}\,\] \[1215.4\overset{0}{\mathop{A}}\,,1.1\times {{10}^{7}}{{m}^{-1}}\] \[5863\overset{0}{\mathop{A}}\,,2.0\times {{10}^{7}}{{m}^{-1}}\]                                          


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