2. Solved Papers
  3. BVP Medical

BVP Medical BVP Medical Solved Paper-2004

  • question_answer
    If you are provided three resistances 2\[8.2\times {{10}^{6}}\], 3\[h=6.6\times {{10}^{-34}}Js\] and 6\[c=3\times {{10}^{8}}m/s\]. How will you connect them so as to obtain the equivalent resistance of 4\[e=1.6\times {{10}^{-19}}C\]:

    A)

    B)

    C)

    D)  None of these

    Correct Answer: C

    Solution :

    In the circuit in option , \[\left[ {{M}^{0}}{{L}^{0}}T{{A}^{0}} \right]\] and 60. Are connected in parallel so, the effective resistance becomes \[\left[ M{{L}^{0}}T{{A}^{0}} \right]\] Then this resistance \[\left[ M{{L}^{0}}T{{A}^{2}} \right]\] is connected with \[\left[ M{{L}^{0}}T{{A}^{-2}} \right]\] resistance in series so as we obtain \[y=5\sin 2\pi \left( \frac{t}{0.04}-\frac{x}{40} \right)\]


You need to login to perform this action.
You will be redirected in 3 sec spinner