BVP Medical BVP Medical Solved Paper-2004

  • question_answer
    The average force necessary to stop a bullet of 20 kg at speed of 250 m/s as it penetrates wood to a distance of 12 cm is :

    A)  \[10\times {{10}^{3}}watt\]                       

    B) \[20\times {{10}^{3}}watt\]

    C)  \[4\times {{10}^{3}}watt\]                         

    D) \[6\times {{10}^{3}}watt\]

    Correct Answer: D

    Solution :

    Here: mass of bullet = 20g = 0.02 kg Speed \[\Omega \] Distance \[\Omega \] Now loss of K.E. \[8.4\times {{10}^{6}}m/s.\] Now from work energy theorem                                 \[2.76\times {{10}^{12}}C/kg\]                 or            \[1.76\times {{10}^{11}}C/kg\]  


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