A) \[\mu F\]
B) \[\mu F\]
C) \[\Omega \]
D) none of these
Correct Answer: A
Solution :
Here: \[\beta =49,\Delta {{I}_{b}}=5.0\mu A\] Current gain in common emitter mode \[\beta =\frac{\Delta {{I}_{c}}}{\Delta {{I}_{b}}}\] or \[\Delta {{I}_{c}}=\beta \times \Delta {{I}_{b}}\] or \[\Delta {{I}_{c}}=49\times 5\mu A=245\mu A\] From the formula \[\Delta {{I}_{e}}=\Delta {{I}_{b}}+\Delta {{I}_{c}}\] \[=(245+5)\mu A=250\mu A\]
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