BVP Medical BVP Medical Solved Paper-2004

  • question_answer
    The power of pump, which can pump 200 kg of water to a height of 50 m in 10sec, will be :

    A)  \[1.76\times {{10}^{-19}}\]                        

    B) \[{{T}_{1}}k\]

    C)  \[{{T}_{2}}k\]                   

    D)  \[\mu \]

    Correct Answer: A

    Solution :

    Here: mass of water m = 200 kg height h = 50m, time t = 10 sec The work done by the pump is given by \[\frac{T}{3}\] \[\frac{\sqrt{3}}{2}T\] Therefore, power of the pump is \[\sqrt{3}T\] \[1.6\times {{10}^{-19}}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner