A) \[6.023\times {{10}^{23}}\]
B) \[6.023\times {{10}^{22}}\]
C) \[12.046\times {{10}^{23}}\]
D) none of these
Correct Answer: C
Solution :
The molecular weight of \[C{{O}_{2}}=44\] \[\therefore \] 44 g. \[C{{O}_{2}}\] contains \[C{{O}_{2}}\] molecules \[=6.023\times {{10}^{23}}\] \[\therefore \] 44 g \[C{{O}_{2}}\] contains oxygen atoms \[=2\times 6.023\times {{10}^{23}}\] \[=12.046\times {{10}^{23}}\]
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