A) \[C{{H}_{3}}C{{H}_{2}}\underset{Cl}{\mathop{\underset{|}{\mathop{CH}}\,}}\,-C{{H}_{3}}\]
B) \[C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl\]
C) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}CHC{{l}_{2}}\]
D) none
Correct Answer: A
Solution :
2-chloro butane has a chiral carbon atom, hence only it will show optical activity and will possess two enantiomers (one chiral carbon atom). \[\overset{H}{\mathop{\overset{|}{\mathop{\underset{OH}{\mathop{\underset{|}{\mathop{C{{H}_{3}}C{{H}_{2}}-{{C}^{*}}-C{{H}_{3}}}}\,}}\,}}\,}}\,\]
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