A) \[C{{H}_{3}}COOH\]
B) \[{{H}_{2}}S{{O}_{4}}\]
C) \[HCl\]
D) \[HN{{O}_{3}}\]
Correct Answer: D
Solution :
Lead is soluble in dil. \[HN{{O}_{3}}\]. However, it becomes passive towards cone. \[HN{{O}_{3}}\]. \[3Pb+\underset{dil.}{\mathop{8HN{{O}_{3}}}}\,\xrightarrow{\Delta }3Pb{{(N{{O}_{3}})}_{2}}+2NO+4{{H}_{2}}O\]
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