A) 850 cm/\[{{s}^{2}}\]
B) 996 cm/\[{{\sec }^{2}}\]
C) 720 cm/\[{{\operatorname{s}}^{2}}\]
D) 650 cm/\[{{\sec }^{2}}\]
Correct Answer: A
Solution :
Time period \[=\frac{No.\,\,of\,\,revolutions}{time}=\frac{25}{14}=1.79\sec \] Now angular speed \[\omega =\frac{2\pi }{T}=\frac{2\times 3.14}{1.79}=3.51\,rad/\sec \] Now magnitude of acceleration is given by \[a={{\omega }^{2}}l={{(3.51)}^{2}}\times 80\] \[=985.6cm/{{\sec }^{2}}\] \[=996cm/{{\sec }^{2}}\]You need to login to perform this action.
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