A) amino acids
B) alcohol
C) aromatic acids
D) dicarboxylic acid
Correct Answer: B
Solution :
\[\underset{glu\cos e}{\mathop{{{C}_{6}}{{H}_{12}}{{O}_{6}}}}\,\xrightarrow{zymase}\underset{alcohol}{\mathop{2{{C}_{2}}{{H}_{5}}OH}}\,+2C{{O}_{2}}\]
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