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BVP Medical BVP Medical Solved Paper-2005

  • question_answer
    According to equation,\[{{C}_{6}}{{H}_{6}}(l)+\frac{15}{2}{{O}_{2}}(g)\xrightarrow{{}}3{{H}_{2}}O(l)+6C{{O}_{2}}(g)\] \[\Delta \text{H}=-3264.4\text{ }kJ/mol\]. The energy evolved when 7.8 g of benzene is burnt in air will be:

    A)  \[3.264\text{ }kJ/mol\]                

    B)  \[32.64\text{ }kJ/mol\]

    C)  \[326.4\text{ }kJ/mol\]                

    D)  \[163.22\text{ }kJ/mol\]

    Correct Answer: C

    Solution :

                    \[\underset{(6\times 12+6\times 1=78)}{\mathop{{{C}_{6}}{{H}_{6}}(l)+\frac{15}{2}{{O}_{2}}(g)}}\,\to 3{{H}_{2}}O(l)+6C{{O}_{2}}(g)\]\[\because \] The energy evolved when 78 g. benzene is burnt = 3264.4 kJ/mol \[\therefore \] The energy evolved when 7.8g benzene is burnt                 \[=\frac{3264.4\times 7.8}{78}=326.44kJ/mol\]


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