A) ionic product of water
B) dissociation constant of both weak acid and weak base
C) dissociation constant of weak acid
D) dissociation constant of weak base
Correct Answer: B
Solution :
\[{{K}_{h}}=\frac{{{K}_{\omega }}}{{{K}_{a}}\times {{K}_{b}}}\]from this, it is clear that hydrolysis constant of a salt of weak acid and weak base is inversely proportional to dissociation constant of both weak acid and weak base.
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