BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    If \[{{\varepsilon }_{0}}\]and \[{{\mu }_{0}}\] are respectively the electric permittivity and magnetic permeability of free space, \[\varepsilon \]and\[\mu \] are the corresponding quantities in a medium, the index of refraction of the medium is :

    A) \[\sqrt{\frac{{{\varepsilon }_{0}}{{\mu }_{0}}}{\varepsilon \mu }}\]                         

    B) \[\sqrt{\frac{\varepsilon \mu }{{{\varepsilon }_{0}}{{\mu }_{0}}}}\]

    C) \[\sqrt{\frac{{{\varepsilon }_{0}}\mu }{\varepsilon {{\mu }_{0}}}}\]                         

    D) \[\sqrt{\frac{\varepsilon }{{{\varepsilon }_{0}}}}\]

    Correct Answer: B

    Solution :

                    Refractive index of medium is given by \[n=\sqrt{{{\mu }_{r}}{{\varepsilon }_{r}}}\] Here,       \[\mu ={{\mu }_{0}}\,{{\mu }_{r}}\] \[\Rightarrow \]               \[{{\mu }_{r}}=\frac{\mu }{{{\mu }_{0}}}\] and        \[\varepsilon ={{\varepsilon }_{0}}\,\,{{\varepsilon }_{r}}\] \[\Rightarrow \]               \[{{\varepsilon }_{r}}=\frac{\varepsilon }{{{\varepsilon }_{0}}}\] \[\therefore \]  \[n=\sqrt{\frac{\mu }{{{\mu }_{0}}}.\frac{\varepsilon }{{{\varepsilon }_{0}}}}\sqrt{\frac{\varepsilon \mu }{{{\varepsilon }_{0}}{{\mu }_{0}}}}\]            NOTE: The above expression can be written as                 \[n=\sqrt{\frac{\varepsilon \mu }{{{\varepsilon }_{0}}{{\mu }_{0}}}}=\frac{{{C}_{vacuum}}}{{{C}_{medium}}}\] as            \[{{c}_{v}}=\frac{1}{\sqrt{{{\varepsilon }_{0}}{{\mu }_{0}}}}\] = speed of light in vacuum \[{{c}_{m}}=\frac{1}{\sqrt{\varepsilon \mu }}\]= speed of light in medium


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