A) gamma-rays
B) alpha particles
C) beta-rays
D) X-rays
Correct Answer: A
Solution :
Key Idea: Penetrating power is maximum for which wavelength is minimum. The penetrating power of radiation is directly proportional to the energy of its photon. Energy of photon \[=\frac{hc}{\lambda }\propto \frac{1}{\lambda }\] \[\therefore \] Penetrating power \[\propto \frac{1}{\lambda }\] Since, \[\lambda \] is minimum for \[\gamma -rays\], so, penetrating power is maximum for \[\gamma -rays\].
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