| List-I | List-II |
| A. Diameter of the helix | 1. \[34\,\overset{\text{o}}{\mathop{\text{A}}}\,\] |
| B. Distance between two adjacent | 2. \[20\,\overset{\text{o}}{\mathop{\text{A}}}\,\] |
| C. Distance between 2 complete turns | 3. \[3\,\overset{\text{o}}{\mathop{\text{A}}}\,\] |
| D. Length of the hydrogen bonds | 4. \[4.4\,\overset{\text{o}}{\mathop{\text{A}}}\,\] |
A) A-1 B-3 C-2 D-4
B) A-2 B-4 C-1 D-3
C) A-4 B-2 C-3 D-1
D) A-1 B-4 C-2 D-3
Correct Answer: B
Solution :
DNA was studied by X-ray crystalography by M.H.F. Wilkins and et. and demonstrated that the diameter of helical structure is 20 \[\overset{\,\,\,\,\,\,0}{\mathop{A}}\,\] and a round of about 34 \[\overset{\,\,\,\,\,\,0}{\mathop{A}}\,\] distance between two base pair is 3- 4 \[\overset{\,\,\,\,\,\,0}{\mathop{A}}\,\] and there are 10 base pair in each turn.
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