A) 5
B) 4
C) 3
D) 2
Correct Answer: B
Solution :
Key Idea: The solution to our problem can be found using Keplers 3rd law of planetary motion. Keplers law is given by \[{{T}^{2}}\propto {{r}^{3}}\] \[\therefore \] \[\frac{T_{A}^{2}}{T_{B}^{2}}=\frac{R_{A}^{3}}{R_{B}^{3}}\] \[\therefore \] \[\frac{{{R}_{A}}}{{{R}_{B}}}{{\left( \frac{{{T}_{A}}}{{{T}_{B}}} \right)}^{2/3}}={{(8)}^{2/3}}={{2}^{3\times \frac{2}{3}}}=4\] or \[{{R}_{A}}=4{{R}_{B}}\] Thus, distance of A from the sun is 4 times greater than that of B from the sun.
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