BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    Two simple harmonic motions with the same frequency act on a particle at right angles i.e., along x and y axis. If the two amplitudes are equal and the phase difference is \[\pi \]/2, the resultant motion will be :

    A) a circle

    B) an ellipse with the major axis along y-axis

    C) an ellipse with the major axis along x-axis

    D) a straight line inclined at 45° to the x-axis

    Correct Answer: A

    Solution :

                    The two simple harmonic motions can be given by \[x=a\,\sin \omega t\]                   ?...(i) and                        \[y=a\sin \left( \omega t+\frac{\pi }{2} \right)\]                                 \[y=a\,\cos \,\omega t\]                              ..?.(ii) On squaring and adding Eqs. (i) and (ii), we obtain                 \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}({{\sin }^{2}}\,\omega t+{{\cos }^{2}}\omega t)\] or            \[{{x}^{2}}+{{y}^{2}}={{a}^{2}}\] This is the equation of a circular motion with radius a. NOTE: Simple harmonic motion is of two types : 1. Linear simple harmonic motion 2. Angular simple harmonic motion


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