2. Solved Papers
  3. BVP Medical

BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    In a closed vessel of volume V, a moles of     nitrogen and b moles of oxygen are made to       react to give nitric oxide, according to reactio\[{{N}_{2}}+{{O}_{2}}2NO\] If at equilibrium, 2x of       moles of NO are obtained then:

    A)  \[{{K}_{c}}=\frac{4{{x}^{2}}}{(a-x)\,(b-x)}.\frac{1}{V}\]

    B)  \[{{K}_{c}}=\frac{4{{x}^{2}}}{(a-x)\,(b-x)}.V\]

    C)  \[{{K}_{c}}=\frac{{{x}^{2}}}{(a-x)\,(b-x)}.V\]

    D)  \[{{K}_{c}}=\frac{4{{x}^{2}}}{(a-x)\,(b-x)}\]

    Correct Answer: D

    Solution :

                    For this reaction \[\underset{(a-x)}{\mathop{\underset{a\,mol}{\mathop{{{N}_{2}}}}\,}}\,+\underset{(b-x)}{\mathop{\underset{b\,mol}{\mathop{{{O}_{2}}}}\,}}\,\underset{(2x)}{\mathop{\underset{0}{\mathop{2NO}}\,}}\,\] Thus-      \[{{K}_{c}}=\frac{{{[NO]}^{2}}}{[{{N}_{2}}][{{O}_{2}}]}\]                 \[=\frac{\frac{{{(2x)}^{2}}}{{{V}^{2}}}}{\frac{(a-x)}{V}.\frac{(b-x)}{V}}\]                 \[=\frac{4{{x}^{2}}}{(a-x)(b-x)}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner