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BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    A reaction \[2A\to B\] follows a second order      kinetics. Doubling the concentration of A will       increase the rate of formation of B by a factor of:     

    A)  \[1/4\]                                

    B)  4

    C)  \[1/2\]                                

    D)  2         

    Correct Answer: B

    Solution :

                    Rate \[=k{{[A]}^{2}}\] when concentration is doubled \[r=k[{{(2A)}^{2}}]\]          \[=k.4{{[A]}^{2}}\] The new rate becomes 4 times.


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