A) \[62.32\text{ }L\]
B) \[6.232\text{ }L\]
C) \[623.2\text{ }L~\]
D) \[0.623\text{ }L\]
Correct Answer: B
Solution :
Given P = 750 mm \[=\frac{750}{760}\] atm \[V=?w=7.0g\] \[T={{27}^{o}}C=27+273=300\text{ }K\] \[R=0.0821\], Molecular wt \[(M)=28\] According to ideal gas equation, \[PV=\frac{w}{M}\times R\times T\] \[V=\frac{w\times R\times T}{P\times M}\] \[V=\frac{7\times 760\times 0.0821\times 300}{28\times 750}\] \[=\frac{1308772}{21,000}\] \[=6.232L\]
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