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BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    If \[_{92}{{U}^{235}}\] is assumed to decay only by emitting two a and one \[\beta \]- particles. The possible product of decay is;

    A)  \[_{89}A{{c}^{277}}\]                   

    B)  \[_{89}A{{c}^{235}}\]

    C)  \[_{89}A{{c}^{211}}\]                   

    D)  \[_{89}A{{c}^{237}}\]

    Correct Answer: A

    Solution :

                     \[_{92}{{U}^{235}}{{\xrightarrow[-\beta ]{-2\alpha }}_{89}}A{{c}^{277}}\] Loss of \[\alpha \]-particle decreases atomic number by 2 and mass number by 4, whereas emission of \[\beta \]particle increases atomic number by 1.


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