A) oxidation of potassium hydroxide to potassium peroxide
B) conversion of dichromate ion to chromate
C) reduction of \[Cr\] (VI) to \[Cr\] (III)
D) formation of chromium hydroxide
Correct Answer: B
Solution :
\[\underset{\begin{smallmatrix} Potassium \\ dichromate \\ (red\,orange) \end{smallmatrix}}{\mathop{{{K}_{2}}C{{r}_{2}}{{O}_{7}}}}\,+2KOH\underset{\begin{smallmatrix} Lemon\,yellow \\ (potassium \\ chromate) \end{smallmatrix}}{\mathop{2{{K}_{2}}Cr{{O}_{4}}}}\,+{{H}_{2}}O\]
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