BVP Medical BVP Medical Solved Paper-2006

  • question_answer
    In an AC circuit with voltage V and current I the power dissipated is :

    A)  depends on the phase between V and I

    B) \[\frac{1}{\sqrt{2}}VI\]

    C) \[\frac{1}{2}VI\]

    D) VI

    Correct Answer: A

    Solution :

                    Key Idea: True power = apparent power \[\times \] power factor In an AC circuit with voltage V and current I, the power dissipated is given by \[P=VI\,\,\cos \phi \] where \[\phi \] is the phase and \[\cos \phi \] is the power factor. Thus, the power dissipated, depends upon the phase between voltage V and current I. NOTE: For \[\phi ={{90}^{o}}\], the power is zero. the current is then stated watt less. Such a case will arise when resistance in the circuit is zero.


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