A) \[4.58\times {{10}^{-6}}J/{{m}^{3}}\]
B) \[6.37\times {{10}^{-9}}J/{{m}^{3}}\]
C) \[81.35\times {{10}^{-12}}J/{{m}^{3}}\]
D) \[3.3\times {{10}^{-3}}J/{{m}^{3}}\]
Correct Answer: A
Solution :
Total average energy \[={{\varepsilon }_{0}}E_{rms}^{2}\] \[=8.85\times {{10}^{-12}}\times {{(720)}^{2}}\] \[4.58\times {{10}^{-6}}J/{{m}^{3}}\]
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