A) 6 cm
B) 4 cm
C) 3 cm
D) 1.5 cm
Correct Answer: C
Solution :
Key Idea: Distance between adjacent nodes in half of wavelength. The standard equation of stationary wave is \[6.37\times {{10}^{-9}}J/{{m}^{3}}\] ......(i) where a is amplitude, \[81.35\times {{10}^{-12}}J/{{m}^{3}}\] is wavelength. Given equation is \[3.3\times {{10}^{-3}}J/{{m}^{3}}\] ....(ii) Comparing Eq. (i) with (ii), we get \[{{10}^{-4}}s\] \[{{10}^{-10}}s\] \[{{10}^{-16}}s\] Distance between adjacent nodes \[{{10}^{-1}}s\] \[y=5\sin \frac{\pi x}{3}\cos 40\pi t\]
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