BVP Medical BVP Medical Solved Paper-2007

  • question_answer
    If a 2 kW boiler is used every day for 1 h, then electrical energy consumed by boiler in thirty days is

    A)                  15 unit                

    B)                  60unit

    C)                  120 unit                              

    D)                  240 unit

    Correct Answer: B

    Solution :

                    Key Idea: The rate at which electrical energy (W) 15 dissipated into other form of energy is called electric power (P) Power = rate of electrical energy \[=0.002cm\]     \[K=\frac{1}{2}m{{v}^{2}}\] \[p=\sqrt{2m\,K}\]          \[{{m}_{1}}=1g,\,{{m}_{2}}=9g,\,{{K}_{1}}={{K}_{2}}=K\] Also 1 kWh or 1 unit is the quantity of electric energy which is dissipated in 1 h in a circuit when the electric power in the circuit is 1 kWh. \[\therefore \]Energy consumed in 30 days \[\frac{{{p}_{1}}}{{{p}_{2}}}=\frac{\sqrt{2\times 1\times K}}{\sqrt{2\times 9\times K}}=\frac{1}{3}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner