A) 1 A
B) 0.5A
C) 0.2A
D) 0.1 A
Correct Answer: D
Solution :
The coefficient of self-induction of a coil is numerically equal to the emf (e) induced in the coil when the rate of change of current \[n\propto \frac{1}{l}.\] in the coil is unity. \[n=\frac{1}{2l}\sqrt{\frac{T}{m}}\] \[{{l}_{1}}=50cm,\,{{l}_{2}}=\left( 1-\frac{2}{100} \right)\times 50=49cm.\] \[\frac{{{n}_{1}}}{{{n}_{2}}}=\frac{{{l}_{2}}}{{{l}_{1}}}=\frac{49}{50}\] \[\Rightarrow \] Given, \[{{n}_{2}}=\frac{50}{49}\times 392=400\], \[={{n}_{2}}-{{n}_{1}}=\] \[=400-392=8\] \[y=2\,a\,\sin \,\frac{2\pi }{\lambda }\,x\cos \frac{2\pi }{\lambda }ct\] \[\lambda \] Induced current \[y=5\sin \frac{\pi \,\,x}{3}\,\cos \,40\,\pi \,t\]
You need to login to perform this action.
You will be redirected in
3 sec
