A) \[12\times {{10}^{23}}\]
B) \[26\times {{10}^{23}}\]
C) \[34\times {{10}^{23}}\]
D) \[48\times {{10}^{23}}\]
Correct Answer: D
Solution :
Formula \[N{{a}_{4}}[Fe{{(CN)}_{6}}]\] sodium Ferro cyanide suggests that it has four sodium atoms. Number of Na atoms = no. of moles \[\times \] no. of atoms per molecule x Avogadro number \[=2\times 4\times 6.023\times {{10}^{23}}\] \[=48\times {{10}^{23}}\]
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