A) 10.8 cm of Hg
B) 14.9 cm of Hg
C) 21.8 cm of Hg
D) 38.8 cm of Hg
Correct Answer: A
Solution :
Key Idea: Boyles law \[({{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}})\]is used to solve this problem. Given, \[{{P}_{1}}=76cm\]of Hg (initial P at NTP) \[{{P}_{2}}=?\] \[{{V}_{1}}=5L,\,\,{{V}_{2}}=30+5=35L\] \[{{P}_{1}}{{V}_{1}}={{P}_{2}}{{V}_{2}}\] \[76\times 5={{P}_{2}}\times 35\] or \[{{P}_{2}}=\frac{76\times 5}{35}=10.8cm\] of Hg
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